๐Ÿ“– Contents Chapter 1 ยท Real Numbers & Exponents
College Algebra · Chapter 1

Real Numbers & Exponents

Almost everyone who struggles in algebra is not actually struggling with algebra — they are struggling with a handful of arithmetic rules that were taught quickly, years ago, and never revisited. This chapter goes back and sets those rules down carefully: what kinds of numbers exist, how they behave when you add and multiply them, what order operations happen in, and how exponents work. Nothing here is beyond you, and nothing here will be rushed. Every rule gets a reason, and every example gets worked out one visible step at a time. Get this chapter solid and the rest of algebra stops feeling like guesswork.

By the end of this chapter you can

  • Name the natural, whole, integer, rational, irrational, and real numbers, and sort any given number into the right sets.
  • Convert a repeating decimal into a fraction, and explain why that proves the number is rational.
  • State and apply the commutative, associative, distributive, identity, and inverse properties by name.
  • Explain why subtraction and division are not commutative or associative, and why division by zero is undefined.
  • Evaluate any numerical expression using the correct order of operations, including signed numbers and grouping symbols.
  • Apply the product, quotient, power, zero, and negative exponent rules, and state the restrictions each one carries.
  • Write very large and very small numbers in scientific notation and multiply, divide, and add them.

Section 1The real number system

Diagram showing the classes of numbers nested inside one another, from natural numbers out to real numbers
Reference. The classes of numbers, nested inside one another — each set contains all of the sets drawn inside it. Source and licence: see the figure credits

Start with counting, then notice what is missing

The first numbers anyone learns are the ones you count with: 1, 2, 3, 4, and onward forever. These are the natural numbers (often written N), sometimes called the counting numbers. They are enormously useful and badly incomplete. Try to count the sheep in an empty field and you need a number the naturals do not contain. Add zero and you have the whole numbers (W): 0, 1, 2, 3, and up.

Now try to record a temperature of eight degrees below zero, or a checking account that is 40 dollars overdrawn. You need numbers on the other side of zero. Attach the negatives and you have the integers (Z): …, −3, −2, −1, 0, 1, 2, 3, … Notice the pattern already forming. Each new set keeps everything the old set had and adds the piece that was missing. Every natural number is a whole number; every whole number is an integer. That nesting is exactly what the figure above is showing you.

Rational numbers: anything you can write as a fraction

Integers still cannot handle half a pizza. A rational number (Q, for quotient) is any number that can be written as a ratio of two integers — that is, as (a)/(b) where a and b are integers and b ≠ 0. That restriction is not decoration. Division by zero is undefined, so a denominator of zero is never allowed, and you will see that condition attached to fractions for the rest of your mathematical life.

Rationals are a bigger group than they first appear. Every integer is secretly a fraction: 7 = (7)/(1), and −12 = (−12)/(1). Every terminating decimal is a fraction: 0.25 = (25)/(100) = (1)/(4). And — this one surprises people — every repeating decimal is a fraction too. In decimal form, a rational number either stops or falls into a repeating block. There is no third option.

Irrational numbers, and the real number line

Some decimals never stop and never repeat. Those are the irrational numbers. The famous ones are √2 = 1.41421356…, π = 3.14159265…, and e = 2.71828182…, and none of them can be written as a fraction of two integers — that is a fact that can be proved, not just a failure to find the right fraction. Careful: √9 = 3 is perfectly rational. It is only the square roots that do not come out evenly that land in the irrational pile.

Put the rationals and the irrationals together and you get the real numbers (R) — every number that has a place on the number line, with no gaps anywhere. Every real number is exactly one point on that line, and every point on that line is exactly one real number. One last restriction worth knowing now: √−4 is not a real number, because no real number multiplied by itself gives a negative result. Even roots of negatives step outside the real number system entirely.

SetSymbolWhat is in itExamplesWhat it still cannot do
NaturalN1, 2, 3, 4, …7, 250No zero, no negatives, no fractions
WholeW0, 1, 2, 3, …0, 19No negatives, no fractions
IntegerZ…, −2, −1, 0, 1, 2, …−12, 0, 45No fractions
RationalQAny (a)/(b), a and b integers, b ≠ 0(3)/(4), −0.25, 0.666…, 8Cannot express √2 or π
Irrational—Decimals that never end and never repeatπ, √2, √10, eCannot be written as a fraction of integers
RealRAll rationals and all irrationals togetherEverything on the number lineCannot express √−4

Worked example: turning a repeating decimal into a fraction

Here is the trick that proves repeating decimals are rational. Let us convert 0.727272… step by step, showing every line.

Step 1 — name the number. Let x = 0.727272…

Step 2 — shift the decimal past one full repeating block. The block "72" is two digits long, so multiply both sides by 102 = 100:
100x = 72.727272…

Step 3 — subtract the original equation from the new one. The infinite tails are identical, so they cancel:
100x − x = 72.727272… − 0.727272…
99x = 72

Step 4 — solve for x. Divide both sides by 99:
x = (72)/(99)

Step 5 — reduce. Both 72 and 99 are divisible by 9. 72 ÷ 9 = 8 and 99 ÷ 9 = 11, so
x = (8)/(11)

Step 6 — check. Divide 8 by 11 by hand: 8.000 ÷ 11 gives 0.7272… ✓ The original decimal comes back, so the answer is right. And since 8 and 11 are both integers with 11 ≠ 0, the number 0.727272… is rational — exactly as promised.

"Non-repeating" has to mean truly non-repeating. A calculator screen that shows 3.141592654 has simply run out of room; it has not told you the digits stop. Never decide a number is rational or irrational from what a calculator displays. Decide it from where the number came from: a ratio of integers, a terminating decimal, or a repeating block means rational — period.
Interactive Drop any of nine numbers into the nested sets and step through the reasoning that walks it inward โ€” natural, whole, integer, rational, irrational, real โ€” including why 0 is whole but not natural, why every repeating decimal is a fraction, and why the square root of 9 is secretly a counting number. Open full ↑
Key points
  • The sets nest: natural ⊂ whole ⊂ integer ⊂ rational ⊂ real.
  • A rational number is any (a)/(b) with integers a, b and b ≠ 0; in decimal form it terminates or repeats.
  • An irrational number has a decimal that never ends and never repeats — π, e, and roots like √2 that do not come out evenly.
  • The real numbers are all rationals plus all irrationals, filling the number line with no gaps; an even root of a negative is not real (√−4 has no real value), though odd roots such as the cube root of −8 do.

Section 2Properties of real numbers

Diagram illustrating the commutative property of a binary operation, showing a operation b equals b operation a
Reference. The commutative property pictured as an operation on a pair — swapping the order of the inputs leaves the result unchanged. Source and licence: see the figure credits

Five rules you already use without naming

You have been using these properties for years without ever calling them by name. The reason to learn the names now is that textbooks, instructors, and test questions will ask you to justify a step, and "because that's how it works" is not an answer they accept. Each property is a promise about what you are allowed to rearrange without changing the value.

The commutative property says order does not matter: a + b = b + a, and a · b = b · a. The associative property says grouping does not matter: (a + b) + c = a + (b + c), and (ab)c = a(bc). The distributive property is the one that connects multiplication to addition: a(b + c) = ab + ac. It is the single most-used property in all of algebra, and it runs in both directions — expanding when you read it left to right, factoring when you read it right to left.

The identity properties name the two numbers that change nothing: a + 0 = a (zero is the additive identity) and a · 1 = a (one is the multiplicative identity). The inverse properties name the partner that undoes a number: a + (−a) = 0 (the opposite, or additive inverse) and a · (1)/(a) = 1 (the reciprocal, or multiplicative inverse) — and that second one carries a restriction, a ≠ 0, because (1)/(0) does not exist.

Where these properties do not apply

This is where careless work goes wrong. Commutative and associative apply to addition and multiplication only. Subtraction and division get neither. Check it yourself with real numbers: 8 − 3 = 5 but 3 − 8 = −5, so subtraction is not commutative. And 12 ÷ 4 = 3 but 4 ÷ 12 = (1)/(3), so division is not commutative either. Grouping fails the same way: (12 − 5) − 2 = 7 − 2 = 5, while 12 − (5 − 2) = 12 − 3 = 9. Same numbers, same order, different grouping, different answer.

There is a repair, though, and it is worth internalizing: rewrite subtraction as adding the opposite, and rewrite division as multiplying by the reciprocal. Once 8 − 3 becomes 8 + (−3), you are back in addition and all the addition properties return. This is why algebra teachers keep saying "subtraction is just addition in a costume."

PropertyAddition formMultiplication formNumerical check
Commutativea + b = b + aab = ba4 + 9 = 9 + 4 = 13
Associative(a+b)+c = a+(b+c)(ab)c = a(bc)(2·5)·3 = 2·(5·3) = 30
Distributivea(b + c) = ab + ac6(10 + 3) = 60 + 18 = 78
Identitya + 0 = aa · 1 = a−7 + 0 = −7; −7 · 1 = −7
Inversea + (−a) = 0a · (1)/(a) = 1, a ≠ 05 + (−5) = 0; 5 · (1)/(5) = 1

Worked example: naming every property in a simplification

Simplify 3(2x − 5) + 4x, and justify each step by name.

Step 1 — rewrite the subtraction as adding the opposite so the distributive property applies cleanly:
3(2x − 5) + 4x = 3 [ 2x + (−5) ] + 4x

Step 2 — distribute the 3 across both terms (distributive property):
= 3(2x) + 3(−5) + 4x

Step 3 — do the arithmetic inside each product. 3 · 2 = 6, and 3 · (−5) = −15:
= 6x + (−15) + 4x

Step 4 — move 4x next to 6x (commutative property of addition):
= 6x + 4x + (−15)

Step 5 — group the like terms (associative property of addition):
= (6x + 4x) + (−15)

Step 6 — factor out the x (distributive property, read right to left):
= (6 + 4)x + (−15)

Step 7 — finish the arithmetic. 6 + 4 = 10, and "+ (−15)" is written as "− 15":
= 10x − 15

Check with a number. Let x = 2. Original: 3(2·2 − 5) + 4·2 = 3(4 − 5) + 8 = 3(−1) + 8 = −3 + 8 = 5. Simplified: 10(2) − 15 = 20 − 15 = 5. ✓ They match, so the simplification is trustworthy.

The distributive property as a mental-math shortcut

Watch how much work the distributive property saves. To compute 7 × 98 without a calculator, notice that 98 = 100 − 2:

7 × 98 = 7(100 − 2) = 7(100) − 7(2) = 700 − 14 = 686

That is the same property you will use to expand 7(x − 2) into 7x − 14. Numbers and variables obey identical rules — that is really the whole idea behind algebra.

Division by zero is undefined, and here is why. Asking "what is 6 ÷ 0?" is asking "what number times 0 gives 6?" Nothing times zero gives 6, so there is no answer. And 0 ÷ 0 is worse: every number times 0 gives 0, so there is no single answer. That is why 0 is the one real number with no reciprocal, and why every fraction you ever write carries a silent "denominator ≠ 0."
Interactive Step through four worked problems and match every algebraic move to the property of real numbers that justifies it โ€” with area models, balance scales, and a live test-value slider that proves no legal step ever changes the value. Open full ↑
Key points
  • Commutative = order can change; associative = grouping can change. Both apply to addition and multiplication only.
  • Distributive, a(b + c) = ab + ac, is the workhorse — it expands one way and factors the other.
  • Identities: 0 for addition, 1 for multiplication. Inverses: −a for addition, (1)/(a) for multiplication with a ≠ 0.
  • Rewrite subtraction as adding the opposite and division as multiplying by the reciprocal to get the properties back.

Section 3Order of operations

An arithmetic expression drawn as a tree, showing which operations are performed first
Reference. An expression drawn as a tree — the operations at the bottom happen first and feed their results upward. Source and licence: see the figure credits

Why an order is needed at all

Take the expression 2 + 3 × 4. Add first and you get 5 × 4 = 20. Multiply first and you get 2 + 12 = 14. Both are defensible readings, and that is intolerable — an expression has to mean one thing. So mathematicians agreed on a fixed order, and everyone from your calculator to a spacecraft's flight software follows it. The correct value is 14, because multiplication outranks addition.

The agreed order is often remembered as PEMDAS: Parentheses, Exponents, Multiplication and Division, Addition and Subtraction. But that acronym misleads thousands of students every year, so read the next sentence twice. Multiplication and division sit on the same level and are done left to right as they appear; addition and subtraction sit on the same level and are also done left to right. PEMDAS has four levels, not six.

LevelWhat you doDirectionWatch out for
1. GroupingParentheses, brackets, and hidden groupers: fraction bars, radicals, absolute valueInnermost firstA fraction bar groups the whole top and the whole bottom
2. ExponentsPowers and rootsRight to left when powers are stacked−32 is not the same as (−3)2; a stacked 232 means 29 = 512, not 82 = 64
3. Multiply / DivideBoth, at the same rankLeft to right8 ÷ 2 × 4 is 16, not 1
4. Add / SubtractBoth, at the same rankLeft to right10 − 4 + 3 is 9, not 3

Signed numbers, carefully

Most order-of-operations mistakes are really sign mistakes. Four rules cover nearly everything. When you multiply or divide, same signs give a positive and different signs give a negative: (−6)(−7) = 42, but (−6)(7) = −42. When you add two numbers with the same sign, add their sizes and keep the sign: −5 + (−8) = −13. When you add two numbers with different signs, subtract the smaller size from the larger and keep the sign of the larger: −9 + 4 = −5. And subtracting is adding the opposite: 6 − (−4) = 6 + 4 = 10.

Then there is the single most common exponent-with-signs trap. In −32, the exponent attaches only to the 3, so you square first and negate second: −32 = −(3 · 3) = −9. In (−3)2, the parentheses make −3 the base, so (−3)2 = (−3)(−3) = 9. Those two expressions differ by more than a sign — they are different questions.

ExpressionWhat the base isWorkValue
−323 (the minus is applied after)−(3 · 3)−9
(−3)2−3(−3)(−3)9
(−3)3−3(−3)(−3)(−3) = 9 · (−3)−27
−333−(3 · 3 · 3)−27

Worked example: a full expression, one step at a time

Evaluate 8 + 3(7 − 2 · 5)2 ÷ 9 − (−4). Nothing gets skipped.

Step 1 — work inside the parentheses first. Inside, multiplication outranks subtraction, so 2 · 5 = 10:
= 8 + 3(7 − 10)2 ÷ 9 − (−4)

Step 2 — finish inside the parentheses. 7 − 10 = −3:
= 8 + 3(−3)2 ÷ 9 − (−4)

Step 3 — exponents. The base is −3 because of the parentheses, and (−3)(−3) = 9:
= 8 + 3 · 9 ÷ 9 − (−4)

Step 4 — multiplication and division, left to right. The leftmost is 3 · 9 = 27:
= 8 + 27 ÷ 9 − (−4)

Step 5 — continue left to right. 27 ÷ 9 = 3:
= 8 + 3 − (−4)

Step 6 — addition and subtraction, left to right. 8 + 3 = 11:
= 11 − (−4)

Step 7 — subtracting a negative is adding a positive. 11 + 4 = 15.

Notice how much of the difficulty lived in Steps 3 and 7 — the two places signs mattered. That is typical.

Worked example: substituting values into an expression

Evaluate b2 − 4ac when a = 2, b = −5, and c = −3. (You will meet this exact expression again as the discriminant of the quadratic formula.)

Step 1 — substitute, and put every negative value in parentheses. This one habit prevents most sign errors:
b2 − 4ac = (−5)2 − 4(2)(−3)

Step 2 — exponents first. (−5)(−5) = 25:
= 25 − 4(2)(−3)

Step 3 — multiply left to right. 4 · 2 = 8:
= 25 − 8(−3)

Step 4 — keep multiplying. 8 · (−3) = −24:
= 25 − (−24)

Step 5 — subtract the negative. 25 + 24 = 49.

Worked example: the fraction bar as a grouping symbol

Evaluate (4 − 2(−3))/((−1)2 + 4). A fraction bar silently wraps parentheses around the entire numerator and the entire denominator, so both must be finished before you divide.

Step 1 — numerator, multiplication first. 2(−3) = −6, so the numerator is 4 − (−6) = 4 + 6 = 10.

Step 2 — denominator, exponent first. (−1)2 = (−1)(−1) = 1, so the denominator is 1 + 4 = 5.

Step 3 — now divide. (10)/(5) = 2.

Before dividing, always confirm the denominator is not zero. Here it is 5, so the expression is defined. If a denominator ever works out to 0, the expression is undefined and there is no value to report.

The most-missed problem on the internet. Evaluate 8 ÷ 2 × 4. Multiplication and division share a rank, so you go strictly left to right: 8 ÷ 2 = 4, then 4 × 4 = 16. Doing the multiplication first because "M comes before D in PEMDAS" gives 8 ÷ 8 = 1, and it is wrong. Same warning for 10 − 4 + 3: left to right gives 6 + 3 = 9, not 10 − 7 = 3.
Interactive Step through four expressions one operation at a time, then re-run each in the wrong order and watch the same symbols land on a different answer. Open full ↑
Key points
  • Order: grouping → exponents → multiply/divide → add/subtract — four levels, not six.
  • Multiplication/division and addition/subtraction are each done left to right, not in acronym order.
  • Fraction bars, radicals, and absolute-value bars are invisible parentheses.
  • −a2 squares first and negates second; (−a)2 squares the negative. Put substituted negatives in parentheses every time.

Section 4Integer exponents

Note. The properties of exponents collected in one place — each rule is a shortcut for expanding and cancelling factors.

What an exponent actually abbreviates

An exponent is nothing but repeated multiplication written compactly. In a5, the number a is the base and 5 is the exponent or power, and it means a · a · a · a · a — five factors of a. Every exponent rule you are about to learn can be rediscovered by writing out the factors and cancelling. That is worth knowing, because it means you never have to memorize a rule you cannot reconstruct.

Watch the product rule appear on its own. Take a3 · a2 and expand: (a · a · a)(a · a) = a · a · a · a · a = a5. Three factors plus two factors is five factors, so am · an = am+n. You add exponents when multiplying like bases — and note "like bases" is required. a3 · b2 cannot be combined at all.

The zero and negative exponent rules are not arbitrary

Students are often told "anything to the zero power is 1" with no explanation, and it feels like a made-up rule. It is not. Compute (23)/(23) two different ways. By plain arithmetic, (8)/(8) = 1. By the quotient rule, 23−3 = 20. Both answers describe the same quantity, so 20 = 1. The same argument works for any nonzero base, which is exactly why the rule carries the restriction a ≠ 0 — 00 is undefined, because the argument would require dividing 0 by 0.

Negative exponents come from the same move. Compute (23)/(25) both ways. Arithmetic: (8)/(32) = (1)/(4). Quotient rule: 23−5 = 2−2. So 2−2 = (1)/(4) = (1)/(22). In general a−n = (1)/(an) with a ≠ 0. Say this out loud once and it will stick: a negative exponent does not make a number negative — it moves the factor to the other side of the fraction bar. So 2−3 = (1)/(8), a positive number, and (1)/(x−4) = x4.

RuleStatementRestrictionExample
Productam · an = am+nSame base; a ≠ 0 if either exponent is negativex4 · x6 = x10
Quotient(am)/(an) = am−na ≠ 0(x9)/(x2) = x7
Power of a power(am)n = amna ≠ 0 if either exponent is negative(x3)5 = x15
Power of a product(ab)n = anbna, b ≠ 0 if n is negative(3x)2 = 9x2
Power of a quotient((a)/(b))n = (an)/(bn)b ≠ 0((x)/(2))3 = (x3)/(8)
Zero exponenta0 = 1a ≠ 0(−5)0 = 1, but −50 = −1
Negative exponenta−n = (1)/(an)a ≠ 03−2 = (1)/(9)

Worked example: simplifying with negative exponents

Simplify (12x5y−3)/(3x−2y4) and write the answer with positive exponents only. State any restrictions.

Step 0 — state restrictions before you touch anything. The variables sit in denominators (and y−3 is itself a denominator in disguise), so we need x ≠ 0 and y ≠ 0. Everything below assumes that.

Step 1 — separate the expression into number, x, and y pieces:
= (12)/(3) · (x5)/(x−2) · (y−3)/(y4)

Step 2 — divide the numbers. 12 ÷ 3 = 4:
= 4 · (x5)/(x−2) · (y−3)/(y4)

Step 3 — apply the quotient rule to x. Subtract the exponents, and be careful with the double negative: 5 − (−2) = 5 + 2 = 7:
= 4x7 · (y−3)/(y4)

Step 4 — apply the quotient rule to y. −3 − 4 = −7:
= 4x7y−7

Step 5 — clear the negative exponent by moving that factor to the denominator:
= (4x7)/(y7)    for x ≠ 0, y ≠ 0

Check with numbers. Let x = 1 and y = 2. Original: (12 · 1 · 2−3)/(3 · 1 · 24) = (12 · (1)/(8))/(3 · 16) = (1.5)/(48) = 0.03125. Answer: (4 · 1)/(27) = (4)/(128) = 0.03125. ✓

Worked example: a negative power of a whole group

Simplify (2a3b−1)−2, positive exponents only, with a ≠ 0 and b ≠ 0.

Step 1 — the outer exponent hits every factor inside (power of a product):
= 2−2 · (a3)−2 · (b−1)−2

Step 2 — multiply the exponents (power of a power). 3 · (−2) = −6 and (−1)(−2) = 2:
= 2−2 · a−6 · b2

Step 3 — evaluate 2−2. It equals (1)/(22) = (1)/(4):
= (1)/(4) · a−6 · b2

Step 4 — move a−6 to the denominator and collect:
= (b2)/(4a6)    for a ≠ 0, b ≠ 0

A quick sanity check on Step 3: the answer must be positive, since 2−2 is a positive fraction. If you had written −4 there, the negative exponent trap caught you.

The exponent rules do not distribute over addition. (x + y)2 is not x2 + y2. Test it with x = 3 and y = 4: the left side is (3 + 4)2 = 72 = 49, and the right side is 9 + 16 = 25. Powers distribute over multiplication and division, never over addition or subtraction. When you are unsure of any rule, plug in small numbers — a single counterexample settles it.
Interactive A worked-step machine for the product, quotient, power, zero, and negative rules โ€” each one expanded factor by factor, with a live slider explorer that lets readers set their own exponents and watch the counting. Open full ↑
Key points
  • Multiplying like bases adds exponents; dividing subtracts them; a power of a power multiplies them.
  • a0 = 1 for a ≠ 0, because an ÷ an equals both 1 and a0.
  • a−n = (1)/(an), a ≠ 0 — a negative exponent relocates a factor, it never makes the value negative.
  • Powers distribute over products and quotients, never over sums: (x + y)2 ≠ x2 + y2.

Section 5Scientific notation

Diagram showing how a large number is rewritten in scientific notation as a coefficient times a power of ten
Reference. A large number rewritten in scientific notation — the decimal point moves and the power of ten records how far. Source and licence: see the figure credits

The form, and the one rule that defines it

Real quantities are frequently absurd to write out. The mass of Earth is about 5,970,000,000,000,000,000,000,000 kilograms; the diameter of a hydrogen atom is about 0.000000000106 meters. Counting those zeros is an invitation to error, so we use scientific notation: every number is written as

a × 10n,   where   1 ≤ |a| < 10   and   n is an integer

That condition on a is the whole rule, and it is strict: exactly one nonzero digit sits to the left of the decimal point. So 5.97 × 1024 is proper scientific notation, while 59.7 × 1023 and 0.597 × 1025 are equal in value but not in proper form. The exponent n is positive for large numbers (|a × 10n| of 10 or more), zero when the number itself already sits between 1 and 10, and negative for small ones (absolute value between 0 and 1), which gives you an instant sanity check on any answer.

Worked example: converting in both directions

Large number. Write 5,970,000,000,000,000,000,000,000 in scientific notation.

Step 1 — place the decimal so exactly one nonzero digit is in front of it. That puts it between the 5 and the 9: 5.97

Step 2 — count how many places the decimal moved. It started at the far right end of the number and moved left 24 places.

Step 3 — moving left means a positive exponent (you shrank a huge number, so the power of ten must build it back up):
5,970,000,000,000,000,000,000,000 = 5.97 × 1024 kg

Small number. Write 0.000000000106 in scientific notation.

Step 1 — place the decimal after the first nonzero digit. The first nonzero digit is 1, so the number becomes 1.06

Step 2 — count the move. From 0.000000000106 the decimal moved right 10 places to sit after the 1.

Step 3 — moving right means a negative exponent:
0.000000000106 = 1.06 × 10−10 m

Going back the other way. To expand 3.4 × 10−5, move the decimal 5 places left, filling with zeros: 0.000034. To expand 2.9 × 106, move 6 places right: 2,900,000.

Written outScientific notationDecimal movedSign of exponent
7,5007.5 × 1033 places leftPositive (number > 10)
62,000,0006.2 × 1077 places leftPositive
11 × 100no moveZero
0.00454.5 × 10−33 places rightNegative (0 < number < 1)
0.000000828.2 × 10−77 places rightNegative
−0.00031−3.1 × 10−44 places rightNegative (the sign of the number is separate)

Worked example: multiplying and dividing

This is where Section 4 pays off — the exponent rules do all the work.

Multiply: (3.2 × 105)(4.5 × 10−9)

Step 1 — regroup so the decimals are together and the powers of ten are together (commutative and associative properties, doing real work):
= (3.2 × 4.5)(105 × 10−9)

Step 2 — multiply the decimals. 3.2 × 4.5 = 14.4

Step 3 — add the exponents (product rule). 5 + (−9) = −4:
= 14.4 × 10−4

Step 4 — fix the form. 14.4 is not between 1 and 10, so rewrite 14.4 as 1.44 × 101:
= 1.44 × 101 × 10−4 = 1.44 × 10−3

Divide: (6.4 × 107)/(8.0 × 10−3)

Step 1 — split into a decimal quotient and a power-of-ten quotient:
= (6.4)/(8.0) × (107)/(10−3)

Step 2 — divide the decimals. 6.4 ÷ 8.0 = 0.8

Step 3 — subtract the exponents (quotient rule), watching the double negative: 7 − (−3) = 7 + 3 = 10:
= 0.8 × 1010

Step 4 — fix the form. 0.8 is less than 1, so write it as 8.0 × 10−1:
= 8.0 × 10−1 × 1010 = 8.0 × 109

Worked example: adding requires a matching exponent

Add 4.2 × 106 + 3.5 × 105. You cannot simply add the decimals here, because the two terms are not measured in the same size unit — one is in millions, the other in hundred-thousands.

Step 1 — rewrite the smaller term to match the larger exponent. To raise the exponent from 5 to 6, shift the decimal one place left: 3.5 × 105 = 0.35 × 106. (Check: 0.35 × 1,000,000 = 350,000, and 3.5 × 100,000 = 350,000. ✓)

Step 2 — now both terms carry 106, so factor it out (distributive property):
= (4.2 + 0.35) × 106

Step 3 — add the decimals. 4.2 + 0.35 = 4.55:
= 4.55 × 106

Step 4 — confirm the form. 4.55 sits between 1 and 10, so the answer is already proper. Written out, that is 4,550,000 — which matches 4,200,000 + 350,000. ✓

Read the exponent as a size, not as decoration. 103 is a thousand, 106 a million, 109 a billion, 10−3 a thousandth, 10−6 a millionth. When an answer comes out as 6.02 × 1023, you should immediately feel "enormous," and when it comes out as 9.1 × 10−31, you should feel "vanishingly small." That instinct catches keystroke errors faster than any recheck.
Interactive Drag an exponent and watch the decimal point walk across the digits, then step through converting real numbers into scientific notation and multiplying and dividing without ever writing out the zeros. Open full ↑
Key points
  • Proper form is a × 10n with 1 ≤ |a| < 10 and n an integer.
  • Numbers of absolute value 10 or more get a positive exponent; those of absolute value between 0 and 1 get a negative one. The sign of the number itself is carried by a and never by n.
  • To multiply, multiply the decimals and add the exponents; to divide, divide the decimals and subtract them.
  • To add or subtract, first rewrite the terms so both carry the same power of ten, then factor it out.

The chapter in one breath

  • The number sets nest: natural ⊂ whole ⊂ integer ⊂ rational ⊂ real, with the irrationals filling the remaining gaps on the number line.
  • A number is rational exactly when it can be written (a)/(b) with integers and b ≠ 0 — equivalently, when its decimal terminates or repeats.
  • Commutative (order) and associative (grouping) apply to addition and multiplication only; the distributive property links the two and both expands and factors.
  • Identities are 0 and 1; inverses are −a and (1)/(a), and 0 has no reciprocal because division by zero is undefined.
  • Order of operations runs grouping → exponents → multiply/divide → add/subtract, with the middle two levels each worked left to right.
  • −a2 and (−a)2 are different expressions; parenthesize every negative you substitute.
  • Exponents add when you multiply like bases, subtract when you divide, and multiply for a power of a power; a0 = 1 and a−n = (1)/(an), both requiring a ≠ 0.
  • Scientific notation is a × 10n with 1 ≤ |a| < 10; multiplying adds exponents, dividing subtracts them, and adding requires matching them first.

ReferenceWords worth knowing

A quick reference for the vocabulary in this chapter — skim it now, and come back whenever a word in a problem statement slows you down.

Absolute value
The distance a number sits from zero on the number line, always zero or positive: |−7| = 7 and |7| = 7. The bars also act as a grouping symbol.
Associative property
Regrouping does not change the result: (a+b)+c = a+(b+c) and (ab)c = a(bc). Applies to addition and multiplication only.
Base
In an, the number a being repeatedly multiplied. In −32 the base is 3; in (−3)2 the base is −3.
Commutative property
Reordering does not change the result: a+b = b+a and ab = ba. Applies to addition and multiplication only.
Distributive property
a(b+c) = ab+ac. Read left to right it expands; read right to left it factors.
Exponent
The small raised number telling how many factors of the base to multiply; also called the power.
Identity property
Adding 0 or multiplying by 1 leaves a number unchanged: a+0 = a, a·1 = a.
Integers
The whole numbers together with their negatives: …, −2, −1, 0, 1, 2, …
Irrational number
A real number whose decimal never terminates and never repeats, so it cannot be written as a ratio of integers — for example π, e, and √2.
Multiplicative inverse (reciprocal)
The number that multiplies with a to give 1, namely (1)/(a). Defined only for a ≠ 0.
Natural numbers
The counting numbers 1, 2, 3, 4, … — no zero, no negatives, no fractions.
Opposite (additive inverse)
The number that adds with a to give 0, namely −a. Every real number has one, including 0 itself.
Order of operations
The agreed sequence for evaluating an expression: grouping, then exponents, then multiplication and division left to right, then addition and subtraction left to right.
Power
Either the exponent itself or the whole expression an, depending on context; "3 to the fourth power" means 34 = 81.
Radical sign
The symbol √ indicating a root. It acts as a grouping symbol, so everything under it is evaluated before the root is taken.
Rational number
Any number expressible as (a)/(b) with a and b integers and b ≠ 0; equivalently, any terminating or repeating decimal.
Real number
Any number with a location on the number line — every rational and every irrational number together.
Repeating decimal
A decimal in which a block of digits recurs forever, such as 0.727272… Every repeating decimal is rational.
Scientific notation
Writing a number as a × 10n with 1 ≤ |a| < 10 and n an integer.
Undefined
Having no value in the given number system — as with division by zero, 00, or √−4 within the real numbers.
Whole numbers
The natural numbers together with 0: 0, 1, 2, 3, …

Check yourself

1. Classify each number into every set it belongs to (natural, whole, integer, rational, irrational, real): −6, 0, (3)/(4), √16, √7.
−6: integer, rational, real. 0: whole, integer, rational, real. (3)/(4): rational, real. √16: natural, whole, integer, rational, real. √7: irrational, real. The trap is √16, which simplifies to 4 — a perfectly ordinary natural number. A radical sign by itself does not make a number irrational; only a root that does not come out evenly does.
2. Convert 0.363636… to a fraction in lowest terms, showing your work.
(4)/(11). Let x = 0.363636… The repeating block has 2 digits, so 100x = 36.363636… Subtract: 100x − x = 36, so 99x = 36 and x = (36)/(99). Divide top and bottom by 9: (4)/(11). Check: 4 ÷ 11 = 0.3636… ✓
3. Name the property illustrated by each statement: (a) 5(x + 3) = 5x + 15; (b) 7 + x = x + 7; (c) (2 · 3) · 4 = 2 · (3 · 4); (d) −9 · 1 = −9; (e) 6 · (1)/(6) = 1.
(a) distributive; (b) commutative property of addition; (c) associative property of multiplication; (d) multiplicative identity; (e) multiplicative inverse. A useful cue: if the order changed it is commutative, if only the parentheses moved it is associative, and if a multiplication got spread across a sum it is distributive.
4. Show with a specific numerical counterexample that subtraction is not associative.
(12 − 5) − 2 = 7 − 2 = 5, but 12 − (5 − 2) = 12 − 3 = 9. Same numbers in the same order, only the grouping changed, and the answers differ — so subtraction has no associative property. Rewriting as 12 + (−5) + (−2) puts you back in addition, where regrouping is safe.
5. Evaluate 20 − 6 ÷ 3 × 2 + 42.
32. Exponent first: 42 = 16, giving 20 − 6 ÷ 3 × 2 + 16. Now multiply and divide left to right: 6 ÷ 3 = 2, then 2 × 2 = 4, giving 20 − 4 + 16. Finally add and subtract left to right: 20 − 4 = 16, then 16 + 16 = 32.
6. Explain the difference between −42 and (−4)2, and give the value of each.
−42 = −16 and (−4)2 = 16. Without parentheses the exponent attaches only to the 4, so you square first and apply the negative afterward: −(4 · 4) = −16. With parentheses the base is −4, so (−4)(−4) = 16. This is why you should wrap every negative value in parentheses when you substitute it.
7. Evaluate b2 − 4ac for a = 3, b = −4, c = 1.
4. Substitute with parentheses: (−4)2 − 4(3)(1). Exponent first: (−4)(−4) = 16. Then multiply left to right: 4 · 3 = 12, and 12 · 1 = 12. Finally 16 − 12 = 4.
8. Evaluate (−8 + 2(5))/(32 − 9) — and be careful.
Undefined. The numerator is −8 + 2(5) = −8 + 10 = 2. The denominator is 32 − 9 = 9 − 9 = 0. Since division by zero has no value, the expression is undefined — the answer is not 0, and it is not 2. Always evaluate the denominator before reporting a quotient.
9. Simplify (−2x4)3 and state any restriction.
−8x12, with no restriction needed. The exponent 3 applies to every factor inside: (−2)3 · (x4)3. Now (−2)(−2)(−2) = −8, and the power of a power multiplies exponents: 4 · 3 = 12. No variable sits in a denominator and no exponent is negative, so x may be any real number — including 0.
10. Simplify (15a−2b6)/(5a3b−1) with positive exponents only, and state the restrictions.
(3b7)/(a5), for a ≠ 0 and b ≠ 0. Numbers first: 15 ÷ 5 = 3. For a, subtract exponents: −2 − 3 = −5, giving a−5. For b: 6 − (−1) = 6 + 1 = 7, giving b7. So the result is 3a−5b7, and moving a−5 into the denominator gives (3b7)/(a5).
11. Explain why 20 = 1 rather than 0, and state the one base for which the rule fails.
Because (23)/(23) equals both (8)/(8) = 1 and 23−3 = 20, the two must be equal, so 20 = 1. The rule fails for base 0: 00 is undefined. The same argument works for any nonzero base, which is exactly where the restriction a ≠ 0 comes from — with a = 0 the argument would require dividing 0 by 0.
12. Compute (2.4 × 10−3)(5.0 × 108) and write the result in proper scientific notation.
1.2 × 106. Multiply the decimals: 2.4 × 5.0 = 12. Add the exponents: −3 + 8 = 5, giving 12 × 105. That is not proper form because 12 is not between 1 and 10, so rewrite 12 as 1.2 × 101: 1.2 × 101 × 105 = 1.2 × 106. Written out, 1,200,000 — and 0.0024 × 500,000,000 does indeed equal 1,200,000. ✓
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